All categories

3 years ago

2n+7+7n=13+3n+8n please help

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

6 0

2n+7+7n=13+11n

7+9n=13+11n

9n-11n=13-7

-2=6

-2/-2 6/-2

-3

By the way that( / )means division lol

Rasek [7]3 years ago

3 0

first combine like terms so 2n + 7n which is 9n

so 9n + 7 = 13 + 3n + 8n

then combine on other side so 9n + 7 = 13 + 11n

then subtract 7 to 13 so 6

sp 9n + 6 = 11n

then subtract 9 to the other side so 2n

6 = 2n then divide all by 2

n= 3

You might be interested in

PLZ HELP!! I'm really stuck<br><br> >n

Bezzdna [24]

A is right one to choose

5 0

3 years ago

HELPPPP ME PLEASE!!!!!

ehidna [41]

Answer:

10/3 ..don't trust I might be wrong

7 0

3 years ago

1 pts

lubasha [3.4K]

Answer: I believe the answer to your question is 4

Step-by-step explanation:

8 0

3 years ago

Solve the system of equations algebraically.

Romashka [77]

A should be the right answer because 4*5/4=5 + 5*2=10 and 5+10=15.

8 0

3 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

<em>Make </em> $R_2$ <em> subject of the formula;</em>

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

3 years ago