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tester [92]
2 years ago
7

PLEASE HELP MEEEE!!!! WILL GIVE BRAINLIEST

Mathematics
1 answer:
Andreas93 [3]2 years ago
7 0

Answer:

The length of the rectangle is equal to 6 cm and the width is equal to 4 cm.

Step-by-step explanation:

Given is : The length of the lab is 32 feet and the width of the lab is 48 feet and each 16 feet of the lab equals 2 centimeters on a scale drawing.

So, We will divide the actual length with 16 and multiply by 2 as 16 feet is equal to 2 cm.

So, length will be =  = 6 cm

Width will be =  = 4 cm

Therefore, the length of the rectangle is equal to 6 cm and the width is equal to 4 cm

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15s-100=350 Can someone answer please.
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Answer:

15s=350+100

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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
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The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

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Answer:

oh my- this actually made me happy-

Step-by-step explanation:

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Mona has 400 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed are
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