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Mashutka [201]
2 years ago
8

Part A: What is the measure of line RV. Part B: What is the measure of line PV​

Mathematics
1 answer:
Korvikt [17]2 years ago
5 0

Answer:

RT=6.5

PV=7.3

Step-by-step explanation:

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Find the zeroes of polynomial x² -(√3+1)x+√3
r-ruslan [8.4K]
X² - √3x -x +√3

x(x-√3) -(x-√3)

(x-√3)(x-1)

zeroes are x-√3 = 0
                 x = √3

and x-1 =0
       x =1
6 0
3 years ago
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
There are 20 students in your class 3/5 of them pack a lunch which meant that will help you find the number of students in your
Leto [7]
So 3/5 of 20 is what
'of' means multiply

3/5 of 20 means
3/5 times 20/1=(3*20)/(5*1)=60/5=12/1=12

12 pack a lunch
8 0
3 years ago
Really need help! Brainliest to correct!
zlopas [31]

Answer:

<u>Given</u>:

  • R(x) = 59x - 0.3x²
  • C(x) = 3x + 14

<u>Find the following</u>:

  • P(x) = R(x) - C(x) = 59x - 0.3x² - 3x - 14 = -0.3x² + 56x - 14
  • R(80) = 59(80) - 0.3(80²) = 2800
  • C(80) = 3(80) + 14 = 254
  • P(80) = 2800 - 254 = 2546
7 0
2 years ago
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
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