Answer:
13.5
Explanation:
Mass: 5kg
Initial Velocity: -15
Final Velocity: 12
Force: 10
We can use the equation: Vf = Vi + at
We need to find acceleration, and we can use the equation, F=ma,
We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.
Now we have all the variables to find time.
Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)
Plugging them in into desmos gives 13.5 for time.
That's good ! I never heard of that before. (Maybe because
I've never been stung by an ant.)
When an ant bites or stings, it injects a tiny amount of 'formic acid'
into your skin. Soon, the formic acid itches, burns, and stings, and
after a while, a little piece of skin dies and falls off. Some people
are seriously allergic to it, and it can make them really sick.
'Acids' and 'bases' are opposites, and one can neutralize (cancel out)
the other. Tony is putting a weak 'base' on the sting, to neutralize the
formic acid that the ant left him as a little gift.
Answer:
Volume of secret cavity = 4 x 10⁻⁶m³
Explanation:
The weight of the sculpture in air is 15.76 N
Mass of the sculpture = 1.61 kg
Mass = Volume x Density
1.61 = V x 8470
Volume of brass =1.90 x 10⁻⁴ m³
When it is submerged in water, the weight is 13.86 N.
That is
Weight of sculpture - Weight of water displaced = 13.86 N
15.76 - Weight of water displaced = 13.86
Weight of water displaced = 1.9 N
Mass of water displaced = 0.194 kg
Mass = Volume x Density
0.194 = V x 1000
Volume of water displaced =1.94 x 10⁻⁴ m³
Volume of secret cavity = Volume of water displaced - Volume of brass material
Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³
Explanation:
First consider that each hand works as a fulcrum: a pivot point where the barbell can rotate.
Now consider only the left hand. If the center of mass of the barbell is between hands (in the middle) it is displaced respect the fulcrum, therefore the weight which is pushing the bar downwards becomes a rotational force. The same thing happens to the other hand. Now, if more weight is added to the left hand the center of mass is displaced towards the left hand and depending how much weight is added, the center of mass will change its position and therefore the torque each hand experiences changes.
If the center of mass is still between hands: The torque remains almost the same changing only the magnitudes but not the direction.
If the center of mass is on the hand: there is no torque for the left hand because there is no leaver.
If the center of mass is to the left: now the torque changes direction and both hands need to stop it in the same direction.
(see diagram below)
