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Paladinen [302]
3 years ago
15

Which waves require a material medium for transmission? a.) light waves b.) radio waves c.) sound waves d.) microwaves

Physics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

mechanical waves require a medium

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PHYSICS HELP PLEASE! will vote brainliest if valid answer! and 20pts!
7nadin3 [17]
The force that pulls the wagon is the horizontal component of the actual force, which is 290*cos(32) = 246N 

4 0
2 years ago
Read 2 more answers
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
When the sphere makes a complete revolution around its circular path, does it spend:_______
topjm [15]

Answer:

Explanation:

the same amount of time in both halves of the circle

5 0
2 years ago
Ultrasound with a frequency of 4.257 MHz can be used to produce images of the human body. If the speed of sound in the body is t
shutvik [7]

Answer:

2.49 * 10^(-4) m

Explanation:

Parameters given:

Frequency, f = 4.257 MHz = 4.257 * 10^6 Hz

Speed of sound in the body, v = 1.06 km/ = 1060 m/s

The speed of a wave is given as the product of its wavelength and frequency:

v = λf

Where λ = wavelength

This implies that:

λ = v/f

λ = (1060) / (4.257 * 10^6)

λ = 2.49 * 10^(-4) m

The wavelength of the sound in the body is 2.49 * 10^(-4) m.

4 0
2 years ago
Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

T^2 = GM/4 pi × r^3

Where G = universal gravitational constant

r = radius

M = masd of jupiter

Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

(T^2 × 4 pi) / (G× r^3) = M

(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3

M = 19.32 /6.672×10^-11)(4.11×10^8)^3

M = 19.32 / 4.63 ×10^15

M = 4.173×10^15kg

6 0
2 years ago
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