The answer is polarization. It is just like when you are on a boat and use polarized glasses so the water wont reflect into your eyes it also intensifies the color of the water so you can see better into the water.
example: you cant see any fish because glare from the sun, put on polarized glasses and now you can see fish up to 30 feet deep.
<u>Answer :</u>
In Normal view of spreadsheet, select area need to be printed. Next, click on Print Area in File menu and then select Set Print Area.
<u>Explanation:</u>
In spreadsheet, a particular area can be selected for printing by the following steps :
Step1: Open the spreadsheet where you wanted to select the area.
Step 2: Select or highlight the cells which you want to print either using the mouse or keyboard. To select using mouse click and drag the mouse across the cells you need to select. To select using keyboard, hold down CTRL key and highlight.
Step 3: Go to the page layout tab.
Step 4: In page layout tab select Print Area icon.
Step 5: Now a pop up appears with two option namely set print area and clear print area.
Step 6: Select set print area. Now the selected range of cells can printed.
<span>A theory of motivation by Steven Reiss, the 16 Basic Desires Theory talks about the sixteen fundamental needs, values and drives that motivate a person.</span>
Given:
The mass of the copper cylinder is: m = 76.8 g = 0.0768 kg
The change in the temperature is: T = 86.5 deg C - 19.5 deg C = 67 deg C
The specific heat is: c = 0.092 cal/g.C
To find:
Heat energy needed to heat the copper cylinder.
Explanation:
The specific heat is defined as the amount of heat energy needed to raise the temperature of a substance by one degree celcius.
The expression relating heat Q, mass m, specific heat c and temperature difference T is:
![Q=mcT](https://tex.z-dn.net/?f=Q%3DmcT)
Substitute the values in the above equation, we get:
![\begin{gathered} Q=76.8\text{ g}\times0.092\text{ Cal/g.C}\times67\text{ deg C} \\ \\ Q=473.40\text{ Cal} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Q%3D76.8%5Ctext%7B%20g%7D%5Ctimes0.092%5Ctext%7B%20Cal%2Fg.C%7D%5Ctimes67%5Ctext%7B%20deg%20C%7D%20%5C%5C%20%20%5C%5C%20Q%3D473.40%5Ctext%7B%20Cal%7D%20%5Cend%7Bgathered%7D)
Final answer:
473.40 calories of heat is required to heat the copper cylinder.