Explanation:
The given data is as follows.
= 57 kg,
= 79 kg
= 6.5 m,
= (6.5 - 1.9) m = 4.6 m
(a) The sum of torque ends about far end is as follows.
= 0
= 0
T = 828 N
Therefore, 828 N is the tension in the cable closer to the painter.
(b) Now, we will calculate the sum about close ends as follows.
= 0
T= 506 N
Therefore, 506 N is the tension in the cable further from the painter.
1. After the collision, their velocities have switched. This is Newton's third law of motion.
2. The total momentum is conserved.
3. The same thing would happen if the collision is totally elastic.
For 4 and 5.
Using the conservation of momentum equation
m1v1 + m2v2 = m1'v1' + m2'v2'<span />
An educated guess is a “hypothesis”