The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is
∑ F = F[a] - F[f] - F[air] = ma
3100 N - 200 N - F[air] = (650 kg) (3 m/s²)
Solve for F[air] :
F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)
F[air] = 3100 N - 200 N - 1950 N
F[air] = 950 N
Explanation:
Given that,
Frequency of the power line, f = 6 Hz
Value of maximum electric field strength of 11.6 kV/m
(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :




(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.
(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :

So, the maximum magnetic field strength is
.
ONEEEEEEEEEEEEEEEEEEEEEEEEE
6 months with no sunrise and the other 6 without a sunset, at some places on Earth, are the result of the orientation of Earth's axis.