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3 years ago

Find the value of each variable.

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

What variable can you give the problem?

zloy xaker [14]3 years ago

5 0

The viariables are unknown because we do know what what we need to find lel

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3 years ago

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3 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

adell [148]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ factoring 96

since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

using exponent rule - $(a^{b}) ^{c} = a^{bc}$

$\sqrt{2^{5} } = 2^{5/2}$

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

doing some simple simplification and $4=2^{2}$ and 6=2*3

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

collecting the roots on one side and applying exponent rule

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$

7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

combining all powers of 2

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

Simplifying

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

8 0

3 years ago

Read 2 more answers

Mrs. Tanaka is making graham crackers. The recipe calls for 115 g. of honey and 375 g of flour. She has only 46 g of honey. How

tino4ka555 [31]

Answer:

150

Step-by-step explanation:

You have 2 ratios

Recipe

115 g H

375 g F

115/375

Mrs. Tanaka's limitations

46 H

? F

Equate these two

115/375 = 46/x Cross multiply

115x = 375 * 46 Combine the right

115x = 17250 Divide by 115

115/115 x = 17250/115 Divide

x = 150 grams of flour,

4 0

4 years ago

Help plz.....................

bonufazy [111]

Answer:

Step-by-step explanation:

Remark

The trick here is convert what you have to Ax + By = C

Solution

Given

y - 3 = 1/2 ( x + 6) Multiply both sides by 2

Solve

2(y - 3) = 2 * 1/2 (x + 6) Do the multiplication
2(y - 3) = x + 6 Remove the brackets
2y - 6 = x + 6 Add 6 to both sides.
2y - 6 + 6 = x + 6 + 6 Combine
2y = x + 12 Subtract x from both sides.
-x + 2y = x - x + 12 Combine
-x + 2y = 12

Answer

A = - 1
B = 2
C = 12

When you multiply through by - 1 you get x - 2y = - 12 which is A

7 0

3 years ago