Since you're given the base for the perimeter of the rectangle, you can solve this question quickly.
First, you multiply 21 by 2, because there are two bases to a rectangle.
You'll get 42, and you will have to do 60-42 to find the perimeter for the remaining two sides.
60-42 will give you 18, so you can divide that by 2 because there are two other sides, giving you 9.
Now you have the side lengths 21 and 9. Area is base*height, so you can multiply 21*9 and get 189.
Therefore, the area of the rectangle is 189 meters
Answer:
Step-by-step explanation:
Answer:
A. Fail to reject the claim that the average math SAT score is 498 when in fact it is not 498.
Step-by-step explanation:
Type II Error:
A type II error happens when there is a non-rejection of a false null hypothesis.
In this question:
The null hypothesis is H0:μ=498.
Since there is a type II error, there was a failure to reject the claim that the average math SAT score is 498 when in fact it is not 498, and thus, the correct answer is given by option A.
You just multiply top times top and bottom times bottom and then find a number you can divide into the number and you keep doing that until you can't simplify any more.
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%