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mash [69]
2 years ago
9

On a graph with y values ranging from 1020 to 9192 what is a reasonable scale to use on a y axis with 10 marks?

Mathematics
1 answer:
Roman55 [17]2 years ago
6 0
Hundred thousands that is your correct answer
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8.1 ÷ 0.9+0.4^3 ÷ 0.8 ⋅ 30
EastWind [94]

Answer:

11.4

Step-by-step explanation:

7 0
2 years ago
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Watch help
babymother [125]

Answer:

m∠RPQ = 8°

Step-by-step explanation:

m∠QRS = 4x - 15

m∠RPQ = x + 1

m∠PQR = x - 2

m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

m∠QRS = m∠RPQ + m∠PQR      {Exterior angle property of triangle}

4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2          {Combine like terms}

4x - 15 = 2x - 1        {Subtract 2x from both sides}

4x - 2x - 15 = - 1

2x - 15 = - 1                  {Add 15 to both sides}

2x = -1 + 15

2x = 14          {Divide both sides by 2}

x = 14/2

x = 7

m∠RPQ = x + 1 = 7 + 1 = 8°

4 0
3 years ago
Read 2 more answers
Under which angle conditions could a triangle exist? Check all that apply.
Lena [83]

Answer: 3 acute angles

and 2 acute angles, 1 obtuse angle

and 2 acute angles, 1 right angle

Step-by-step explanation:

the key is just to imagine it

also you have to know that right angle is 90° acute is less than 90° and obtuse is more than 90°

7 0
3 years ago
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An index that is a standardized measure used in observing infants over time is approximately normal with a mean of 90 and a stan
weqwewe [10]

Answer:

The proportion of children that have an index of at least 110 is 0.0478.

Step-by-step explanation:

The given distribution has a mean of 90 and a standard deviation of 12.

Therefore mean, \mu = 90 and standard deviation, \sigma = 12.

It is given to find the proportion of children having an index of at least 110.

We can take the variable to be analysed to be x = 110.

Therefore we have to find p(x < 110), which is left tailed.

Using the formula for z which is p( Z < \frac{x - \mu}{\sigma}) we get p(Z < \frac{110 - 90}{12} = 1.67).

So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)

Using the Z - table we can calculate p(Z < 1.67)  = 0.9522.

Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478

Therefore the proportion of children that have an index of at least 110 is 0.0478

8 0
3 years ago
Meow help me pls :(((
pentagon [3]

Answer:

a) 3x-5=16

b) 30cm

Step-by-step explanation:

a) 5(x-1)=2(x+8)

   5x-5=2x+16

   5x-2x-5=16

      3x-5=16

b) solving the equation gives x=7

put x=7 into first line, 5(7-1)=30cm

to check we can place it into second one as well

2(7+8)=30cm

   

5 0
2 years ago
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