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3 years ago

Solve for side AB. Show all your work Please help!

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

7 0

Given triangle is a right angle triangle so we are allowed to use trigonometric formulas.

We want to find Hypotenuse using angle A and base 7 cm

so right choice is to use cosine

$\cos(A)=\frac{AC}{AB}$

$\cos(25^{\circ})=\frac{7}{AB}$

$0.90631=\frac{7}{AB}$

$AB=\frac{7}{0.90631}$

$AB=7.72362657369$

Hence value of side AB is approx 7.72 cm.

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What is the value of x? 45° 2 (2x - 5) > n

Vladimir [108]

Answer:

70 degrees

Step-by-step explanation:

Find the diagram attached

The sum of the angles is supplementary that is

45 + 2x- 5 = 180

2x + 40 = 180

2x = 180 - 40

2x = 140

x = 140/2

x = 70

Hence the value of x is 70 degrees

4 0

3 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

3 years ago

Whats 4485 square feet of grass in 3/4 of an hour. How many square feet of grass can be fertilized per hour

alex41 [277]

4485 square feet of grass ... 3/4 of an hour
x square feet of grass = ? ... 1 hour

If you would like to know how many square feet of grass can be fertilized per hour, you can calculate this using the following steps:

4485 * 1 = 3/4 * x
4485 = 3/4 * x /*4/3
x = 4485 * 4 / 3
x = 5980 square feet

Result: 5980 square feet of grass can be fertilized in one hour.

7 0

3 years ago

What is the area of this triangle ?

Liula [17]

Answer:

Step-by-step explanation:

area of a triangle= b x h x 1/2 or b x h /2

the base is 4 and the height is 4

4x4/2

=16/2

5 0

3 years ago

Five less than three times a number

Radda [10]

That would turn into 3x-5

4 0

3 years ago