m∠A + m∠B = 90
(3x + 5) + (2x - 15) = 90
(3x + 2x) + (5 - 15) = 90
5x - 10 = 90
+ 10 + 10
5x = 100
5 5
x = 20
m∠A = 3x + 5
m∠A = 3(20) + 5
m∠A = 60 + 5
m∠A = 65
m∠B = 2x - 15
m∠B = 2(20) - 15
m∠B = 40 - 15
m∠B = 25
To whatttttttttttt free points?
Answer:
a = A/πb
Step-by-step explanation:
To solve this subject of the formulae given that A = πab.
<u>solution</u>
A = πab
the next step is to look for a unique way to get rid of the variables disturbing "a" from standing alone. this variables are π and b, we need to detach dem from a
A = πab
divide both sides by πb
A/πb = πab/πb
A/πb = a
a = A/πb
therefore the value of a in the fomular A = πab is evaluated to be a = A/πb
Answer:
HGD: 117
FDG: 180
Step-by-step explanation:
Answer:
we need to prove : for every integer n>1, the number 
is a multiple of 5.
1) check divisibility for n=1, 
(divisible)
2) Assume that 
is divisible by 5, 
3) Induction,
Now, 
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between 
and is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
