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jonny [76]
2 years ago
11

from a window 24 feet above the ground, the angle of elevation to the top of another building is 38 degrees. The distance betwee

n the buildings 63 feet. Find the height of the building to the nearest tenth of a foot.

Mathematics
1 answer:
Delvig [45]2 years ago
6 0

Answer:

The  height of the building is 73.2\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

tan(38\°)=\frac{BC}{AB}

we have

AB=63\ ft

substitute and solve for BC

tan(38\°)=\frac{BC}{63}

BC=(63)tan(38\°)=49.2\ ft

Find the height of the building

The  height of the building (h) is equal to

h=BC+24=49.2+24=73.2\ ft

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