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alukav5142 [94]
3 years ago
14

The points (15, 10), (25, 20), (30, 22), (40, 32), (55, 53), (60, 55) represent the time, x, it takes 6 people to travel y miles

. The scatterplot below represents the situation.
Based on the information above, how many miles should a person who drives for 48 minutes expect to travel?
32 miles
42 miles
48 miles
54 miles

Mathematics
2 answers:
Gnoma [55]3 years ago
7 0

Answer:

B, 42 miles.

Step-by-step explanation:

Insert 48 into the equation, 1.04x-7.15. You get 49.92 for 1.04*48. Then, subtract 7.15 from that. This then concludes that y = 42.77, which is rounded to 42.

posledela3 years ago
3 0

Answer:

B. 42 miles

Step-by-step explanation:

just took on edg test. ;)

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strojnjashka [21]
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6 0
3 years ago
Which step is the same when constructing an inscribed square and an inscribed regular hexagon?
Colt1911 [192]

After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.

<h3>What is a regular hexagon?</h3>

A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.

Steps to create an inscribed hexagon:

1: The structure needs to adjust the box thickness towards that radius.

2: Afterward moves around the outside of the circular path to just produce the 6 vertices of that similar hexagon.

"Set the compass to the radius of the circle" so, option C is correct.

Thus the above answer is correct.

Learn more about inscribed hexagons here:

brainly.com/question/21502832

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6 0
2 years ago
Read 2 more answers
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DaniilM [7]

Answer:

what in the world is the first part

Step-by-step explanation:

8 0
3 years ago
A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru
Viktor [21]

Answer:

1) S = 2\cdot w\cdot l - 8\cdot x^{2}, 2) The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l, 3) S = 176\,in^{2}, 4) x \approx 4.528\,in, 5) S = 164.830\,in^{2}

Step-by-step explanation:

1) The function of the box is:

S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)

S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w

S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x

S = 2\cdot w\cdot l - 8\cdot x^{2}

2) The maximum cutout is:

2\cdot w \cdot l - 8\cdot x^{2} = 0

w\cdot l - 4\cdot x^{2} = 0

4\cdot x^{2} = w\cdot l

x = \frac{\sqrt{w\cdot l}}{2}

The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l

3) The surface area when a 1'' x 1'' square is cut out is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}

S = 176\,in^{2}

4) The size is found by solving the following second-order polynomial:

20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}

20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}

8\cdot x^{2} - 164\,in^{2} = 0

x \approx 4.528\,in

5) The equation of the box volume is:

V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x

V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x

V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}

V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}

V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}

The first derivative of the function is:

V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}

The critical points are determined by equalizing the derivative to zero:

12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0

x_{1} \approx 4.952\,in

x_{2}\approx 1.548\,in

The second derivative is found afterwards:

V'' = 24\cdot x - 78\,in

After evaluating each critical point, it follows that x_{1} is an absolute minimum and x_{2} is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

x \approx 1.548\,in

The surface area of the box is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}

S = 164.830\,in^{2}

4 0
2 years ago
6. A rectangle and a parallelogram have the same base and the same height. How are their areas
fomenos

Answer:

the height

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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