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qaws [65]
3 years ago
8

. Which elements were formed in the big bang? A. carbon, oxygen B. hydrogen, helium C. nitrogen, carbon dioxide D. chlorine, arg

on
Physics
2 answers:
salantis [7]3 years ago
8 0
Elements and the 'Big Bang' theory. During the formation of the universe some 14 billion years ago in the so-called 'Big Bang', only the lightest elements were formed – hydrogen and helium along with trace amounts of lithium and beryllium.
Nutka1998 [239]3 years ago
3 0
Hello there!

Well, the Big Bang only formed 3 elements (the rest were formed in stars and supernovae). These are Hydrogen, Helium, and Lithium.

Your correct answer will be b.

I hope this helps!
Brady
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Need help I'll give you 30 points please.
Ksivusya [100]

Cathode Ray Tube i think?

7 0
3 years ago
An apple is falling from a tree. Disregarding air resistance, which diagram shows the free-body diagram of the force
Alex Ar [27]

Answer: Second choice (straight down arrow)

Explanation:

I just did it.

7 0
3 years ago
A proton moving at 5.00 106 m/s through a magnetic field of magnitude 1.78 t experiences a magnetic force of magnitude 7.40 10-1
aliya0001 [1]

The magnetic part using the Lorentz force is: F = q v x B, 
where v and B are vectors and v x B is the vector cross product. 

Magnitude of the force: F = q v B sin(α) 

So, sin(α) = F/( e v B), with e the proton charge. 

This will give you a value for sin(α), and two potentials for its opposite.

You will now look for: 

sin(α) = 7.40 10^-13/( 1.60 10^-19 * 5 10^6 * 1.78) 
= 0.520


So either sin(α) = 0.502 or sin(α) = -0.502 
The 1st α = 30.1 degrees or α = 150 degrees. 
The 2nd α = 210 degrees or α = 330 degrees. 
So we can say that 30.1 degrees and 330 degrees would be minimum and biggest on [0,360]

6 0
3 years ago
Block with mass m =7.6 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.29 m. w
PSYCHO15rus [73]

1) 256.9 N/m

The force applied to the spring is equal to the weight of the block hanging on the spring:

F=mg=(7.6 kg)(9.8 m/s^2)=74.5 N

And the spring constant can be found by using Hook's law, because we know that the displacement caused by this force is x = 0.29 m:

F=kx\\k=\frac{F}{x}=\frac{74.5 N}{0.29 m}=256.9 N/m

2) 1.08 Hz

The angular frequency of oscillation of the spring is given by the formula:

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{256.9 N/m}{7.6 kg}}=5.81 rad/s

And the frequency of oscillation is given by:

\omega=2\pi f\\f=\frac{2 \pi}{\omega}=\frac{2\pi}{5.81 rad/s}=1.08 Hz

3) 2.19 m/s

The velocity at time t of the block is given by:

v=v_0 cos (\omega t)

where

v_0 = 4.4 m/s is the initial velocity of the block

\omega=5.81 rad/s is the angular frequency

t is the time

Substituting t=0.36 s, we find the speed of the block at that time:

v(0.36 s)=(4.4 m/s) ( cos ((5.81 rad/s)(0.36 s)) = -2.18 m/s

And the negative sign means that the direction of the velocity is upward (because the initial velocity was downward)

4) 25.6 m/s^2

The maximum acceleration is given by:

a_0 = \omega^2 A

where A is the amplitude of the oscillation.

We can find the amplitude by using the law of conservation of energy: in fact, the kinetic energy at the equilibrium point must be equal to the elastic potential energy at the point of maximum displacement:

K=U\\\frac{1}{2}mv_0^2 = \frac{1}{2}kA^2\\A=\sqrt{\frac{mv_0^2}{k}}=\sqrt{\frac{(7.6 kg)(4.4 m/s)^2}{256.9 N/m}}=0.76 m

So, the maximum acceleration is

a_0 = \omega^2 A=(5.81 rad/s)^2 (0.76 m)=25.6 m/s^2

5) 95.1 N

The magnitude of the net force acting on the block is given by the difference between the weight and the restoring force of the spring:

F=mg-kx

First, we need to find the position x at t=0.36 s, which is given by

x(t)=A sin(\omega t)=(0.76 m)(sin ((5.81 rad/s)(0.36 s))=0.66 m

And so, the net force is

F=(7.6 kg)(9.8 m/s^2)-(256.9 N/m)(0.66 m)=-95.1 N

And the negative sign means the direction of the force is upward.

8 0
3 years ago
Read 2 more answers
a ring with a clockwise current is situated with its center directly above another ring. The current in the top ring is decreasi
dusya [7]

Answer:

<em>clockwise</em>

<em></em>

Explanation:

when current flows through a ring in a clockwise direction, it produces the equivalent magnetic effect of a southern pole of a magnet on the coil.

Since the current is decreasing, there is a flux change on the lower ring; generating an induced current on the lower ring. According to Lenz law of electromagnetic induction, "the induced current will act in such a way as to oppose the motion or the action producing it". In this case, the induced current will have to be the same  polarity to the polarity of the current change producing it so as to repel the two rings far enough to stop the electromagnetic induction. The induced current will then be in the clockwise direction on the lower ring.

8 0
3 years ago
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