What forces are acting when you try to crack an egg in your palm(will give brainliest)
1 answer:
You might be interested in
Answer:
-2π ≤ ∅ ≤ 3π/2
0 ≤ ∅ ≤ π/2
Explanation:
In simple harmonic motion, the displacement and velocity vectors are as follows:
where ∅ is the phase angle. At t = 0, the initial displacement and velocity are
According to two equations, we need to find the ∅ values which makes both cosine and sine terms positive.
So, ∅ is in the range: [-2π, -3π/2] and [0,π/2]
Your answer for part a is correct. Using Newton's 3rd Law, the force on the rocket by the exhaust leaving the rocket is the same magnitude (opposite direction) as the downward force applied to the exhaust.
In part b the net force is the upward force from the exhaust thrust minus the downward force of gravity:
Then using the Second Law, we get for part c:
The force and acceleration are in the upward direction
In part b the net force is the upward force from the exhaust thrust minus the downward force of gravity:
Then using the Second Law, we get for part c:
The force and acceleration are in the upward direction