What does This equal pls(n+8)+(n-12)

-4x + 7 = 2y - 3<br> y-intercept:<br><br> x intercept:

pantera1 [17]

Answer:

x-intercept: $\bigg(\frac{5}{2}, \:0\bigg)$

y-intercept: $(0,\:5)$

Step-by-step explanation:

To find the x-intercept, substitute in $0$ for $y$ and solve for $x$ .

$-4x + 7 = 2y - 3$

$-4x+7=2\left(\bold{0}\right)-3$

Simplify 2(0): $-4x+7=2\cdot \:0-3$

Subtract 0 - 3 = -3: $-4x+7=-3$

Subtract 7 from both sides: $-4x+7-7=-3-7$

Simplify: $-4x=-10$

Divide both sides by -4 $\frac{-4x}{-4}=\frac{-10}{-4}$

$\bold{x=\frac{5}{2}}$

To find the y-intercept, substitute in $0$ for $x$ and solve for $y$ .

$-4x + 7 = 2y - 3$

$-4(\bold{0})+7=2y-3$

Switch sides: $y-3=-4\left(0\right)+7$

Simplify -4(0): $2y-3=-0+7$

Add 3 to both sides: $2y-3+3=7+3$

Simplify: $2y=10$

Divide both sides by 2: $\frac{2y}{2}=\frac{10}{2}$

$\bold{y=5}$

3 0

2 years ago

The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers

Elis [28]

Answer:

The numbers are 23 and 7

Step-by-step explanation:

1. Set up the equations

Let x = the greater number

and y = the smaller number. Then

(1) x - y = 16

4y = 4 times the smaller number and

4y - 5 = 5 less than 4 times the smaller number. Then

(2) x = 4y - 5

You have a system of two equations:

$\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}$

2. Solve the equations

$\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}$