Does a two-digit number exist such that the digits sum to 9 and when the digits are reversed the resulting number is 9 greater t
2 answers:
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Answer:
so the first picture is it graphed without solving it and the second graph is the answer to it graphed
Step-by-step explanation:
Sum means add
the number is x
13 divided by a number is 13/x
the number divided by the number is x/13
so
also can be simplified to
or
translated it is where x is the number
the number is x
13 divided by a number is 13/x
the number divided by the number is x/13
so
also can be simplified to
translated it is