1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)
2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)
3. Point (-4, 3) lies in Quadrant II
4. Point (6, 0) lies on the x-axis
5. Any line with no slope is parallel to the y-axis
7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1
8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)
9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6
10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True
Answer:
-7 =x
Step-by-step explanation:
−30=5(x+1)
Divide each side by 5
−30/5=5/5 (x+1)
-6 = x+1
Subtract 1 from each side
-6-1 = x+1-1
-7 =x
Answer:
x=-10, y=-20
Step-by-step explanation:
Since both 2x and 3x+10 equals y, they equal each other.
2x = 3x + 10
x = -10
Substitute -10 for x
2(-10) = y
y=-20
Answer:
120
Step-by-step explanation:
The sum of the angles in a quadrilateral is 360 degrees
2t+t+2t+t = 360
6t = 360
Divide by 6
6t/6 = 360/6
t = 60
Angle Z = 2t
Angle Z = 2*60 = 120
