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Fittoniya [83]
4 years ago
15

Students in this class were presented with an unknown lipid. They ran the iodine test on it, producing these results:

Biology
2 answers:
xenn [34]4 years ago
8 0

Answer:

B). It is Crisco

Explanation:

<em>Iodine value</em> can be used to measure the unsaturation (presence of double bonds in fatty acids) of oils and fats. When in <em>solution</em> with the presence of fats, the <em>iodine reacts with the double bonds</em> present and leaves the solution, which can be <em>indirectly measured </em>by observing the <em>change in color</em> (purple to colorless), the results are expressed as \frac{IodineAbsorbed(g)}{100gfat}.

A<em> lower Iodine</em> value indicates a high presence of <em>saturated fatty acids</em>, and a <em>high value</em> indicates a high presence of <em>unsaturated fatty acids</em>, which are better for nutrition.

Some typical values are:

-Fully hydrogenated fats: 1-3 <em>(Crisco is a shortening brand, which is fully hydrogenated fat, solid at room temperature)</em>

-<u>Butterfat</u>: 25-42

-<em>Palm oil</em>: 50-55

-<em>Corn oil</em>: 107-135

-<em>Chia seed oil</em>: 209-211

Ratling [72]4 years ago
6 0
The answer is "C. It is corn oil."
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