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2 years ago

Consider the graph of f(x) = x is shifted up 8 units, what would be the equation of the new graph?

1 answer:

5 0

F(x) = x + 8

This is because you are simply moving the y-intercept up 8 units.

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explain why an circle would have an infinite number of lines of reflection that would carry the circle into itself?

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Circles will never have a side but they only have 1 line that can be counted as a side.

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3 years ago

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The weight of an object on the moon varies directly as its weight on Earth. With all of his gear on, Neil Armstrong weighed 360

babymother [125]

amistre64 Medals 0
e = k.m
360 = k.60
k = 360/60 = 36/6 = 6
108 = 6.m
108/6 = m = 18

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3 years ago

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2 years ago

The figure is made up of a hemisphere and a cylinder.

Goryan [66]

Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$
V (volume) = ?

Solving:(<span>Cylinder volume)
</span> $V = h* \pi *r^2$
$V = 8*3.14*5^2$
$V = 8*3.14*25$
$\boxed{ V_{cylinder} = 628\:cm^3}$

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4 * \pi * \frac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3} 
$

Formula: (<span>Volume of the hemisphere)
</span> $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$

Solving:
$V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}$
$V = \frac{1570}{6}$
$\boxed{V_{hemisphere}\approx 261.6\:cm^3}$

<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
$\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark$

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3 years ago

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model aeroplane is made to a scale of 1 by two of the size of the real plane the area of the wings of the real plane are 40 m sq

4vir4ik [10]

The area of the wings of the model is 100000 square centimeters

<h3>How to determine the model area of the wings?</h3>

The given parameters are:

Scale factor, k = 1/2

Actual area of wings, A = 40 square meters

The model area is calculated as

Model area = Actual area * k^2

This gives

Model area = 40 * (1/2)^2

Evaluate

Model area = 10 square meters

Convert square meters to square centimeters

Model area = 10 * 10000 square centimeters

Evaluate

Model area = 100000 square centimeters

Hence, the area of the wings of the model is 100000 square centimeters