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3 years ago

Ayo helppp ill give u anthing

Mathematics

1 answer:

kicyunya [14]3 years ago

4 0

Answer:

16.9 m

Step-by-step explanation:

Start with a half a circle. The central angle of a semicircle is 180 deg.

Now subtract 21 deg on each side.

180 - 21 - 21 = 138

The central angle is 138 deg.

The radius is 7 m.

Now we use the formula for the length of an arc of a circle given the radius of the circle and the central angle of the arc.

$s = \dfrac{n}{360^\circ}2 \pi r$

$s = \dfrac{138^\circ}{360^\circ}2(3.14159)(7~m)$

$s = 16.9~m$

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Find all real solutions of the equation. (Enter your answers as a comma-separated list.)

34kurt

Answer:

0,1

Step-by-step explanation:

x^2 − x = 0

Factor out an x

x(x-1) =0

Using the zero product property

x=0 x-1=0

Solving each equation

x=0 x-1+1 =0+1

x=0 x=1

The solutions are

x=0,1

7 0

3 years ago

The diagram shows a circle inside a square 16cm Work out the area of the circle

vesna_86 [32]

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3 years ago

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17. Find the reflection of the point A(6.-1) in the x-axis.

castortr0y [4]

Answer:

Your answer will be (6,1)

Step-by-step explanation:

I know this because a reflection over the x-axis is (x,y) -> (x,-y) If you apply this to (6,-1) you get (6,1).

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2 years ago

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

$z=\frac{x}{y}$

we have

$x=12\ cm$

$y=9\ cm$

substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

Find the area of the larger figure

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

$z^{2}=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

$x=390*16/9=693.33\ cm^{2}$

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2 years ago

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Ierofanga [76]

Step-by-step explanation:

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3 years ago