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3 years ago

One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

Answer:

29119.66666...+14561.3333...=43681, 209ft^2, not square feet.

Step-by-step explanation:

"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"

Ok, so this is a tricky one- 209 feet squared, not 209 square feet, therefore the area is 209^2, or 43,681.

Next, let's define our variables-

x= the "other side"

z= 3 feet shorter than twice side

We can now make these (useful) equations

z=2x-3

43681= (2x-3)+x

We will focus on the latter for now-

Simplify

43681= (2x-3)+x

43681= 2x-3+x

43681= 3x-3

43684=3x

14561.3333...=x

z=2x-3

z=2*(14561.3333)-3

z=29119.66666....

29119.66666...+14561.3333...=43681

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