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Ilya [14]
3 years ago
8

One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

Answer:

29119.66666...+14561.3333...=43681, 209ft^2, not square feet.

Step-by-step explanation:

<em>"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"</em>

Ok, so this is a tricky one- <em> 209 feet squared, </em>not 209 square feet, therefore the area is 209^2, or 43,681.

Next, let's define our variables-

<em>x= the "other side"</em>

<em>z= 3 feet shorter than twice side</em>

We can now make these (useful) equations

z=2x-3

43681= (2x-3)+x

We will focus on the latter for now-

Simplify

43681= (2x-3)+x

43681= 2x-3+x

43681= 3x-3

+3

43684=3x

/3

14561.3333...=x

z=2x-3

z=2*(14561.3333)-3

z=29119.66666....

29119.66666...+14561.3333...=43681

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