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asambeis [7]
3 years ago
12

Q and R are not mutually exclusive events. If P(Q)=5/8 and P(R)=1/8 and P(Q and R)=1/32,Find P(q or R)

Mathematics
2 answers:
artcher [175]3 years ago
8 0
The solution for this problem is just adding and subtracting fractions. We all know how to add and subtract function because our teacher since high school teach us how to. P(Q or R) = P(Q) + P(R) - P(Q and R) = 5/8 + 1/8 - 1/32 = 23/32

The answer to this question is 23/32.
amm18123 years ago
7 0
Given that the events are not mutually exclusive the union of the probability of the events is calculated through the equation,

 P(Q or R) = P(Q) + P(R) - P(Q and R)

Substituting the known values,

P(Q or R) = 5/8 + 1/8 - 1/32

Simplifying,
 
 P(Q or R) = 23/32

The answer to this item is 23/32. 
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3 years ago
Here is a rectangle which has a width of x cm. x cm
miskamm [114]

Answer:

278.25 cm2

Step-by-step explanation:

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=> (x + x + 8) + x + 8 + (x+8) + (x + x + 8) + x + 8 + (x +8) = 90

=> 8x + 48 = 90

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=> x =42/8 = 5.25 (cm)

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3 years ago
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