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ziro4ka [17]
2 years ago
9

So you go to the store one day with 50$ to spend. You wanna buy some apples and some pears. The apples are 5$ per pack (3 in eac

h pack) and the pears are 3$ each pack (4 in each pack.) you end up buying 5 packs each fruit. How much money do you have left over?
Mathematics
2 answers:
Lesechka [4]2 years ago
4 0

Answer:

10$

Step-by-step explanation:

Illusion [34]2 years ago
4 0

Answer:

$10

Step-by-step explanation:

Honestly, who eats that much fruit? but okay, we'll start with finding how much money she spent, and apples will go first:

So this is basically dealing with rates, so you just gotta multiply:

5 x 5 = 25

So you spent an unnecessary $25 on apples, now let's go to pears:

3 x 5 = 15

So you spent $15 on pears, now we combine those two:

25 + 15 = 40

So you spent $40 on fruit

So now we want to know how much money we have left, so we're gonna subtract:

50 - 40 = 10

So you have $10 left over

hope this helps:)

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Rosa runs 3 miles in 42 minutes.

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A.true

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A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra
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Answer:

0.4 = 40% probability that both marbles are blue.

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If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that N = 6

4 blue, which means that k = 4

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that N = 6

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Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

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Total is 100%.

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Both yellow(6.67%)

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40 + 6.67 + x = 100

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x = 53.33

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