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aleksandrvk [35]
3 years ago
8

PLEASE HELP! giving BRAINLIEST AND GIVE CORRECT ANSWER AND EXPLAIN!

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

<em>so</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>0</em><em> </em><em>square</em><em> </em><em>centimeter</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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PLZZZZ HELPPPPPPP!!!!
Vladimir79 [104]

Answer: The height of the building is 50.75 feet.

Step-by-step explanation:

The ratio between the height of the object and the casted shadow must be equal for all the objects, as the angle at which the source if light impacts them is the same.

For the person, we know that it is 5.8ft tall, and the shadow is 3.2ft long.

The ratio will be: 5.8ft/3.2ft = 1.8125

Now, if H is the height of the building, and the shadow that the building casts is 28ft, we must have:

H/28ft = 1.8125

Now we can solve this for H.

H = 1.8125*28ft = 50.75 ft

Then the height of the building is 50.75 feet.

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3 years ago
At the market, 8 apples cost $4, 4. How much do 9 apples cost?
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Step-by-step explanation:


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3 years ago
Multiply<br> 3x( 4x – 3x+5)
Daniel [21]

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The answer is 3x^(2)+15x

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3 years ago
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ehidna [41]

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should get 0.2 hope this helps you!

Step-by-step explanation:

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3 years ago
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What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

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3 years ago
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