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3 years ago

Simplify the following expression : 2 (2x-3)+5 (6x+1)

1 answer:

7 0

To simplify begin by distributing the multiplication outside the parenthesis:
$2(2x-3)+5(6x+1) =4x-6+30x+6 \\ 4x+30x=34x$

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2x-y+3x=. when y is 4 and x is 3.

Gelneren [198K]

2 x 3 - 4 + 3 x 3 = 11

Do PEMDAS.

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Exponents

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3 0

2 years ago

Read 2 more answers

Please help me thank you

Hoochie [10]

Answer:

$\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}$

Step-by-step explanation:

We know:

$\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet$

We have

$\sin\theta=\dfrac{1}{2}$

Use $\sin^2\theta+\cos^2\theta=1$

$\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}$

$\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$

3 0

2 years ago

52<br> base six <br><br> Write the normal number

saveliy_v [14]

19770609664 is simple power of 52⁶ .

What is exponent and power?

A base number raised to an exponent is referred to as a power in mathematics, where base number is the factor that is multiplied by itself and exponent is the number of times the same base number is multiplied.
Exponents and powers are two techniques for simplification of extremely big or extremely small numbers.
As an illustration, we can write 3 x 3 x 3 x 3 as 34, where 4 is the exponent and 3 is the base, if we need to represent it simply.
It is claimed that the entire statement 34 has power.

= 52⁶

= 52 × 52 × 52 × 52 × 52 × 52

= 19770609664

Learn more about Exponent

brainly.com/question/5497425

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4 0

10 months ago

Cedric completed the square for the quadratic expression 5x^2−40x+15 in order to determine the minimum value of the expression,

Olegator [25]

Answer:

Step 3 is not correct (should be $(x-4)^2$ , not $(x+4)^2$