Let θ be an angle in quadrant III such csc(θ)=-(13)/(5). . Find the exact values of tan θ and cosθ ?

1 answer:

3 0

Given that the angle is in quadrant II such that csc(θ) = -(13)/(5), the expression can be expressed into 1/sin (θ) = -(13)/(5). θ can be calculated through the calculator equal to -22.62 degrees. Since the angle is in quadrant II, θ is equal to 180-22.62 ot 157.38 degrees. Tan θ then is equal to -5/12, cos θ is equal to -12/13.

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