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777dan777 [17]
3 years ago
10

Let θ be an angle in quadrant III such csc(θ)=-(13)/(5). . Find the exact values of tan θ and cosθ ?

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0
Given that the angle is in quadrant II such that <span>csc(θ) = -(13)/(5), the expression can be expressed into 1/sin </span>(θ) = -(13)/(5). θ can be calculated through the calculator equal to -22.62 degrees. Since the angle is in quadrant II, <span>θ is equal to 180-22.62 ot 157.38 degrees. Tan </span>θ then is equal to -5/12, cos <span>θ is equal to -12/13.</span>
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