Given that the angle is in quadrant II such that <span>csc(θ) = -(13)/(5), the expression can be expressed into 1/sin </span>(θ) = -(13)/(5). θ can be calculated through the calculator equal to -22.62 degrees. Since the angle is in quadrant II, <span>θ is equal to 180-22.62 ot 157.38 degrees. Tan </span>θ then is equal to -5/12, cos <span>θ is equal to -12/13.</span>
