F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
-30
Step-by-step explanation:
In g(8) the 8 = n. So, substitute 8 in for n in the expression -4n + 2
g(8) = -4(8) + 2 = -32 + 2 = -30
5/7-4/6
take the least common multiple of six and seven
which is 42
5*whatever multiple of 7 that gives you 42
5*6=30
plus
4* whatever multiple of six that gives you 42
4*7=28
subtract 28 from 42
your answer 14
5p² - p - 18 = (5p +9)(p - 2)
Answer:
Question 1: seems all A,B and C are incorrect
Question 2: long = 45/(3*3) =45/9 =5
