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4 years ago

Jessie ran 4 miles in 1 hour. How long did it take Jessie to run one mile? *

Mathematics

2 answers:

elixir [45]4 years ago

5 0

Answer:

15 mins

Step-by-step explanation:

4 miles : 1 hour

1 mile : x hours

x/1 = 1/4

x = ¼ hours

¼ hours = ¼ × 60 = 15 mins

ollegr [7]4 years ago

5 0

Answer: 15 minutes

Step-by-step explanation: 1 hour is 60 minutes, 60 minutes divided by the 4 miles will give you 15 minutes.

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3/7 s = 6 solve to find the number of students

spayn [35]

3/7 s = 6

[multiple by 7/3 on both sides]
s = 14

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4 years ago

You earn $30 for washing 5 cars.how much do you want for washing 3cars

Blizzard [7]

Answer:

$18

Step-by-step explanation:

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3 years ago

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Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane passing through (2 comma 0

SVETLANKA909090 [29]

Answer:

The volume of the tetrahedron is:

$\frac{50}{3}=16.667$

Step-by-step explanation:

The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.

The equation of the plane formed by the three points is:

Points: (2,0,0);(0,5,0);(0,0,4)

$\pi :\frac{x}{2} +\frac{y}{5} +\frac{z}{4} =1$

It can also be expressed as:

$10x + 4y+5z=20$

We have to calculate the triple integral, therefore we must define the domain:

The values of x are given by:

0≤x≤2

We will integrate the values of y between the y = 0 axis and the line formed when z = 0:

z=0 ⇒ 10x + 4y=2 ⇒ $y=\frac{20-10x}{4} =$

$0\leq y \leq 5-\frac{5}{2}x$

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20

10x + 4y+5z=20 ⇒ $z=\frac{20-10x-4y}{5} =4-2x-\frac{4}{5}y$

$0\leq z \leq 4-2x-\frac{4}{5}y$

The volume of the tetrahedron is:

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \ \ \ \int\limits^{4-2x-\frac{4}{5}y }_{0} {z} \, dz\, dy \,dx$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \frac{z^2}{2}|^{4-2x-\frac{4}{5}y}_0\, dy \,dx$

$\frac{z^2}{2}|^{z=4-2x-\frac{4}{5}y}_{z=0}=\frac{5}{25}(5x+2(y-5))^2$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} {\frac{5}{25}(5x+2(y-5))^2}\, dy \,dx$

$\int\limits^{2}_{0} {-\frac{25}{6}(x-2)^3} dx=-\frac{25}{24} (x-2)^4|^{2}_{0}=\frac{50}{3}$

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4 years ago

Jack uses 64 inches of wood to build a rectangular picture frame. The length of one side is 25 inches. What is the length of the

Masteriza [31]

Well, a rectangle has 4 sides and the opposite side is at an equal length so you want to do 25 in. times 2= 50 inches. Then you want to subtract the 50 inched from 64 inches which will equal = 14. Then to get the other side lengths you need to divide it my two which is 7.
So your side lengths are seven inches. The word is side lengths.

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4 years ago

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Factor completely, then place the answer in the proper location on the grid. a ^2 - 25b ^2

nata0808 [166]

The answer:
a^2−25b^2
or
2(a-25b)

Hope this helps!

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