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Pachacha [2.7K]
3 years ago
6

How to find out how many times on one number goes into another number​

Mathematics
1 answer:
labwork [276]3 years ago
4 0
You can find out how many times a number goes into another number by adding.
For example:
7 goes into 21 three times
7+7+7 = 21

Another method would be multiplication
Using the same example
7x3= 21

You could also use division
21 divided 7 = 3
Or
21 divided by 3= 7
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Help pls!!
nexus9112 [7]

Answer: Choice D

Explanation:

The range is the set of all possible y outputs of a function. The highest y can go is y = 1, which occurs at the vertex. We can have y = 1 or y be smaller than this. Therefore, the range is y \le 1

7 0
2 years ago
Give me an example of an irrational number that is greater than 10
Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

5 0
4 years ago
Please and thank you help with math!!
Anvisha [2.4K]

Answer:none of these

Step-by-step explanation:

5 0
3 years ago
The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir
zlopas [31]
   
\displaystyle\\
\begin{cases}
R_1 = 3R_2\\
\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi 
\end{cases} \\  \\ 
\begin{cases} 
R_1 = 3R_2\\
R_1^2 + R_2^2=12 
\end{cases} \\  \\ 
(3R_2)^2+ R_2^2=12 \\  \\ 
9R_2^2 + R_2^2=12 \\  \\ 
10R_2^2=12\\\\
R_2^2 = \frac{12}{10} = \frac{6}{5}  \\  \\ 
R_2 =  \boxed{\sqrt{\frac{6}{5}} } \\  \\ 
R_1 = \boxed{3\sqrt{\frac{6}{5}} }



7 0
3 years ago
Need of helpp for my test​
katrin [286]

Answer:

-2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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