Answer:
3,-3
Step-by-step explanation:
g(3)= (3)³+6(3)²-9(3)-54
= 27+54-27-54
=81-81
= 0
g(-3) = (-3)³+6(-3)²-9(-3)-54
= -27+54+27-54
= 27-27
= 0
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You can solve for sides of a triangle using the following equation.
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
Answer:
sin²2θ. (cos θ sin θ). cos 2θ
Step-by-step explanation:
finding g'(x)
g'(x)
= 4 (cosθsinθ)³ . { cosθ. (sinθ)' + sinθ. (cosθ)' }
- (cosθ)' = - sinθ
- (sinθ)' = cosθ
= 4 (cosθsinθ)³ { cosθ. cos θ + sinθ.(-sin θ)}
= 4 (cosθsinθ)³{ cos²θ - sin²θ}
- cos²θ - sin²θ = cos 2θ
- 2sinθ cosθ = sin 2θ
= (4 cosθ sinθ)². (cosθ sinθ). { cos²θ - sin²θ}
= <u>sin²2θ. (cos θ sin θ). cos 2θ</u>
40x+20=1000
40x-20=1000-20
40x=980
=
x=24.5
It would take 24 and a half months to spend $1000 for the gym membership
