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kvasek [131]
2 years ago
10

Solve the following system of equations by the substitution method.

Mathematics
1 answer:
Dahasolnce [82]2 years ago
6 0

Answer:

Step-by-step explanation:

5x=y+6   --------- equ 1

2x-3y=4  -------- equ 2

5x - 6 = y

y = 5x - 6

substitute in equ 2

2x-3(5x - 6) =4

2x - 3*5x + 3*6 = 4

2x - 15x + 18 = 4

- 13x = 4 - 18

-13x = -14

x = -14/-13

x = 14/13

substitute  in equ 1

5*14/13 = y+6  

70/13 - 6 = y

y =  ( 70 - 78)/13

y = -8/13

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Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

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Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

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That is (20/100)×40000=8000

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Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

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Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

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That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
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