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STALIN [3.7K]
3 years ago
8

(05.03 LC)

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

The correct answer is x = -5

Step-by-step explanation:

All vertical lines can we written in terms of x = (a number). You can find this number in the ordered pair under the x-coordinate. In this case it is -5.

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Can you solve for y plz
vredina [299]
Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
y = 26/3 or 8 1/3 or 8.333 (those are all the same but in different forms)
8 0
3 years ago
Find the range of the function.
borishaifa [10]

Answer:

y >= 8

Step-by-step explanation:

This equation is written in vertex notation, so we know the vertex is (-5,8). The parabola opens upward because the coefficient of the squared term is positive. Therefore, the vertex is the minimum, meaning all y values will be greater than (or equal to) the y-coordinate of the vertex (which is 8). When we convert this into a mathematical inequality, we get y>=8.

7 0
3 years ago
Read 2 more answers
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
Let f(x) = 3x + 5 and g(x) = -4x + 7 find (f o g)(-4)
Keith_Richards [23]
<span>(f o g)(-4)
=-4(3x+5)+7
</span><span>=-4(3(-4)+5)+7</span><span>
= 35</span>
5 0
3 years ago
What is 5/8 times 4? Then simplify your answer.
scZoUnD [109]

The answer is 2 1/2. Because you need to cross cancel then you take the "freeway", and you get 5/2 and simplified is 2 1/2.And since half equals .5 it would be 2.5 just in case you also needed decimal.

Hope I Helped!!!!!!!!!!

=)=)=)=)=)=)

P.S. If you need help you could message me or go to my profile to ask me!!!

=)=)=)

4 0
3 years ago
Read 2 more answers
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