Will give brainliest if right

Assume that human body temperatures are normally distributed with a mean of 98.22 degrees Upper F 98.22°F and a standard deviati

Anna35 [415]

Answer: 0.00102%

Step-by-step explanation:

Given : Human body temperatures are normally distributed with a mean of $\mu=98^{\circ}F$ and a standard deviation of $s=0.61^{\circ}F$

A hospital uses $100.6^{\circ}F$ as the lowest temperature considered to be a fever.

Let x be the random variable that represents the human body temperatures.

$z=\dfrac{x-\mu}{s}$

For x= 100.6, $z=\dfrac{100.6-98}{0.61}=4.26229508197\approx4.26$

Using normal distribution table for z-values for right-tailed area ,

P(x>100.6)= $P(Z>4.26)=0.0000102=0.00102\%$

Hence, the required probability = 0.00102%

8 0

2 years ago

What is the value of x? x-2/5=7

arsen [322]

X=37/5
or 7.4 in decimal form

3 0

2 years ago

Read 2 more answers

Which of the following is a correct conversion of 50 kg

wariber [46]

Answer:

c. 50kg = 50,000g

Step-by-step explanation:

We have to solve these following rule of three to see which of the following is a correct conversion of 50kg.

a)

Each kg has 1000g

So

1kg - 1000g

50kg - xg

x = 50*1000

x = 50,000g

Conversion a) is wrong

b)

Each kg has 1000000mg

So

1kg - 1000000g

50kg - x mg

x = 50*1000000

x = 50,000,000 mg

Conversion b) is wrong

c)

In a), we have already converted 50kg to g. We have verified that 50kg = 50,000g. So c. is correct

d)

In b), we have already converrted 50kg to mg. We have verified that 50kg = 50,000,000g. So d. is wrong

4 0

2 years ago

What is this area? please help

Gnoma [55]

Answer:

60

Step-by-step explanation:

multiply the 20m x 6m

20x6=120. Is base x high

then

divide ➗ by 2

is equal to 60

I hope help you

4 0

2 years ago

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

2 years ago