What does the problem says
The question is incomplete. The complete question is:
Question: What is the expected percent change in the DNA content of a typical eukaryotic cell as it progresses through the cell cycle from the start of the G1 phase to the end of the G2 phase
a. -100%
b. -50%
c. +50%
d. +100%
Answer:
d. +100%
Explanation:
S phase comes between G1 and G2 phases of the interphase of a cell cycle. S phase of interphase includes replication of DNA. The process of DNA replication doubles the amount of DNA present in the cell. The newly synthesized DNA is accommodated in the sister chromatids of chromosomes. Therefore, a cell with 2C DNA in the G1 phase would have 4C DNA at the end of the G2 phase. So, there is a +100% increase in the DNA content of a cell as it proceeds from G1 to the end of the G2 phase.
Answer:
Examples of Beneficial Mutation. Mutation, a change in the sequence of genes, is divided into various types such as beneficial, harmful, and neutral, based on their effects. ... Germ-line mutation occurs in the germ cells, and is inherited by the offspring via the reproduction cells.
Explanation:
Answer:
The correct answer will be-cooperate
Explanation:
Nematodes or ringworms interact with the bacteria in one of three ways: mutualism, parasitism and symbiosis.
The interaction between nematode <em>Steinernema carpocapsae</em> and bacteria <em>Xenorhabdus nematophila</em> prove to be a symbiotic relationship as both the organisms benefit each other.
The interaction between these two organisms is also known as cooperation because both the species can live without each other also. It is during the infective juvenile stage, the bacteria start living in the intestine of the nematode and benefiting the nematode. Both bacteria and nematode help each other killing the host and then utilizing the cadaver of the host.
Thus, cooperate is the correct answer.
