Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40
Answer: The answer is the first explanation.
Step-by-step explanation: We are given five different options and we are to select which explanation is correct to derive the formula for a circumference of a circle.
Let 'C' be the circumference and 'd' be the diameter of a circle. Now, we will write the ratio of the circumference to the diameter as
Also, we know that
And diameter of a circle is twice the radius, so
Therefore,
This is the formula for the circumference of a circle. Since this explanation matches exactly with the first option, so the correct option is
(a). Find the relationship between the circumference and the diameter by dividing the length of the circumference and length of the diameter. Use this quotient to set up an equation to showing the ratio of the circumference over the diameter equals to π . Then rearrange the equation to solve for the circumference. Substitute 2 times the radius for the diameter.
Well, to add fractions, you need to find a common denominator. In this case, the smallest common denominator would be 12. So you must multiply each fraction so that both denominators are 12.
3/4*3/3=9/12
1/3*4/4=4/12
Add those two fractions together, reduce if possible, and you have your answer!
9/12+4/12=13/12
You can't reduce, so 13/12 is your answer.
Hope it helps!
-Lacy
B. because "boring" implies that all classical music is boring.
Answer:
Steps below
Step-by-step explanation:
8) x = y²/2 2rcosΘ = r²sin²Θ 2cosΘ = rsin²Θ
r = 2cosΘ/sin²Θ = 2cotΘcscΘ
9) (x+2)²+y²=4 y= rsinΘ x=rcosΘ
(rcosΘ+2)²+y²sin²Θ = 4
r²cos²Θ+4rcosΘ+4+y²sin²Θ=4
r²(sin²Θ+cos²Θ)+4rcosΘ=0
r²+4rcosΘ=0 r+4cosΘ=0
r = - 4cosΘ
10) r = 2sinΘ r=2* y/r r²=2y x²+y²=2y
x² + (y²-2y+4) = 4 x²+(y-2)² = 4
11) r = 3tanΘsecΘ = 3* (y/x) * (r/x)
1 =3y/x²
x² = 3y 3y = x²
