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garik1379 [7]
3 years ago
11

HELP

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
7 0

Answer:

5.8  or 6

Step-by-step explanation:

round 1149 to 1150

round 199 to 200

your answer would be 5.75 round that to 6

babunello [35]3 years ago
4 0

Answer:

The answer you are looking for is 5.8 times greater  

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3 years ago
Can someone give me the answer
Tasya [4]

Take the 4cm side and the 6cm side.

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That's what choice-B says.


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The circle graph below represents the opinions of 100 students about their favorite sports. Each student chose exactly one of th
bagirrra123 [75]

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8 0
2 years ago
Hometown​ Grocery, Inc. has 50 comma 000 shares of common stock outstanding and 4 comma 000 shares of preferred stock outstandin
Anit [1.1K]

Answer:

$0.36 per share

Step-by-step explanation:

The data provided in the question are as follows

Common stock outstanding = 50,000 shares

Preferred stock outstanding = 4,000 shares

Par value of common stock = $4

Interest rate and par value of preferred stock = 9% and $100

Total dividend payment declared = $54,000

So, the amount of dividend for each share of common stock is

= (Total dividend payment declared - Preferred stock outstanding × interest rate × par value) ÷ (common stock outstanding)

= ($54,000 - 4,000 × $100 × 9%) ÷ (50,000 shares)

= ($54,000 - $36,000) ÷ (50,000 shares)

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7 0
3 years ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& -4~) 
%  (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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