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neonofarm [45]
3 years ago
13

A bag contains 1 yellow ball and 9 red balls . A ball is chosen at random from the bag . what is the best answer for the probabi

lity of drawing the yellow ball?
a) impossible
b) unlikely
c) very likely
d) certain
Mathematics
1 answer:
Strike441 [17]3 years ago
6 0
Your answer is unlikely. That would be a 1 out of 10 chance.
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These marbles are placed in a bag and two of them are randomly drawn. What is the probability of drawing two pink marbles if the
Shalnov [3]

Answer:

2/10 * 2/10 = 1/25

Step-by-step explanation:

Suppose you have 10 marbles in a bag.

5 black , 2 pink and 3 blue

As if two pink marbles are selected then

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probability = event occurred / total outcomes

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Similar probability for an other pink marbles

Probability for the drawing two pink marbles is

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4 0
3 years ago
What are the points of discontinutity y=(x-3)/x^2-12x+27
madreJ [45]

Answer:

(3, -\frac{1}{6})

Step-by-step explanation:

We can rewrite the equation as

y = \frac{x - 3}{(x - 3)(x - 9)}

Notice that we have x - 3 in both the numerator and the denominator, so it looks like we can divide it out. However, what if x - 3 is 0? Then we would have y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}, which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for x = 3, but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at x = 3. In the simplified version of the function, if we plug in x = 3, we get

y = \frac{1}{((3) - 9)} = -\frac{1}{6}

So the point (3, -\frac{1}{6}) is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at x = 9 (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of x

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Select the point that is a solution to the system of inequalities​
ExtremeBDS [4]
<h3>Answer: B.  (-1, 0)</h3>

This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.  

In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality y \le x^2-3x true. So this is why we can rule choice A out.

Choice C is not a solution because (4,1) does not make y \le -x+3 true. This point is not below the red diagonal line. We can cross choice C off the list.

Choice D is similar to choice A, which is why we can rule it out as well.

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