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The answer's
Find an equation in slope intercept form for the line through point P(-3, 2) and perpendicular to the line
1 answer:
Answer:
y=-1/5 x +7/5
Step-by-step explanation:
First lets find the slope for line containing the two points (2,3) and (1,2)
m=5
Two lines are perpendicular between each other if m1*m2=-1
we have one slope m1=5, we obtain m2= -1/5
Next we need to eval the equation for lines y=mx+b, where m= -1/5 using the point P(-3,2)
2=-1/5 * -3 +b
From that we obtain that b= 2-3/5=7/5
So the equation for the desired line is:
y=-1/5 x +7/5
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we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
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therefore, let's just plug that on the remaining ones,
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however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
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recall that
therefore, let's just plug that on the remaining ones,
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