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labwork [276]
3 years ago
13

Find an equation in slope intercept form for the line through point P(-3, 2) and perpendicular to the line

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

y=-1/5 x +7/5

Step-by-step explanation:

First lets find the slope for line containing the two points (2,3) and (1,2)

m=\frac{3-(-2)}{(2-1)}\\

m=5

Two lines are perpendicular between each other if m1*m2=-1

we have one slope m1=5, we obtain m2= -1/5

Next we need to eval the equation for lines y=mx+b, where m= -1/5 using the point P(-3,2)

2=-1/5 * -3 +b

From that we obtain that b= 2-3/5=7/5

So the equation for the desired line is:

y=-1/5 x +7/5

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Write an ordinary number for 0.004
Alexeev081 [22]

Answers;

it would be the second one

Step-by-step explanation:

hope this helps

7 0
3 years ago
A cafeteria charges a fixed price per ounce for the salad bar. A sandwich costs $3.10, and a drink costs $1.75. If a 7-ounce sal
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3 years ago
Three fair quarters are tossed, and a tail appears on at least one of them. What is the probability that at least one head appea
nirvana33 [79]

Answer:

Probability that at least one head appears is\frac{6}{7}

Step-by-step explanation:

Given : Three fair quarters are tossed, and a tail appears on at least one of them.

To find : What is the probability that at least one head appears?

Solution :

When three fair quarters are tossed the sample form is

\{HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\}

According to question,

In a sample space a tail appears on at least one of them.

i.e. Total outcomes is \{HHT,HTH,HTT,THH,THT,TTH,TTT\}=7

Favorable outcome is getting at least one head appears

i.e. Favorable outcome is \{HHT,HTH,HTT,THH,THT,TTH\}=6

Probability that at least one head appears is

\text{Probability}=\frac{\text{Favorable outcome }}{\text{Total outcome}}

\text{Probability}=\frac{6}{7}

Therefore, Probability that at least one head appears is\frac{6}{7}

3 0
4 years ago
Differentiate <br> 1/√x^2-1
xz_007 [3.2K]
The function is f(x)= \frac{1}{ \sqrt{ x^{2} -1}}

write f again as f(x)= (x^{2} -1)^{- \frac{1}{2} } 

(the power -1 takes the expression to the denominator, and the power 1/2 is square root)

writing rational expressions as power expressions, generally makes differentiation more practical.

In f(x)= (x^{2} -1)^{- \frac{1}{2} } we notice 2 functions:

the outer function u^{ -\frac{1}{2} }, where u=x^{2} -1, and the inner, u itself , which is a function of x.

So we differentiate by using the chain rule:

f'(x)= -\frac{1}{2}u^{- \frac{1}{2}-1 }*u'=  -\frac{1}{2}u^{- \frac{3}{2} }*(2x)=- \frac{x}{ \sqrt{ u^{3} } } =- \frac{x}{ \sqrt{ (x^{2} -1)^{3} } }


Answer: - \frac{x}{ \sqrt{ (x^{2} -1)^{3} } }
3 0
3 years ago
Y=-2/3x+3 I'm super stuck
Serhud [2]

Answer:

x=0  y=3

Step-by-step explanation:

4 0
3 years ago
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