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3 years ago

Help with algebra 2 I can’t figure out how to solve the problem .

Mathematics

1 answer:

defon3 years ago

3 0

Answer: D

Step-by-step explanation:

Using the equation plot in the coordinates of the points to see if they fit the equation.

5x-3y < 30

A) 5(-3) -3(5) < 30

-15 -15 < 30

-30 < 30 This is true

B) 5(0) -3(0) < 30

0 - 0 < 30

0< 30 This is true

C) 5(-5) - 3(3) < 30

-25 - 9 < 30

-34 < 30 This is also true

D) 5(3) - 3(-5) < 30

15 + 15 < 30

30 < 30 This is not true because 30 is not greater that 30

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If the density of the full can is 1.2 g/cc what is the mass ?

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3 years ago

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4 What is the number if 61 is 3 less than 8 times the number?

Mrrafil [7]

If 61 is less than 8 times the number then the number is 8.

Given 61 is 3 less than 8 times the number.

Let the number be 'x'.

The term "polynomial" in mathematics refers to a mathematical statement that consists of two or more algebraic terms that are added, subtracted, or multiplied (no division!). Constants and positive exponents are frequently used, together with at least one variable, in polynomial formulas.

we can write the equation as:

8x ₋₋ 3 = 61

arranging the like terms i.e constants.

8x = 61 ₊ 3

8x = 64

to find the value of x, divide 64 by 8.

x = 64 ÷ 8

x = 8

hence the number we get after solving the equation is 8.

Learn more about Polynomials here:

brainly.com/question/1487158

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2 years ago

Solve sin x - (3sin x-1) = 0

soldi70 [24.7K]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}$

Step-by-step explanation:

$\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}$

$\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.$

$\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}$

$\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi$

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3 years ago