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3 years ago

Which equation can be used to solve for x?

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

X+10=24

Step-by-step explanation:

X+10=24 for 6

X+10=24

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Does the point (6, 0) satisfy the equation y = x2?

shtirl [24]

Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.

Y = 6^2 = 36

36 is not 0 so (6,0) is not a solution

6 0

2 years ago

Read 2 more answers

How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

8 0

3 years ago

What is the slope of a line that passes through (-12,15) and (0,4)

pav-90 [236]

Answer:

D. -11/12

Step-by-step explanation:

7 0

2 years ago

The radius of the base of the cylinder is 10 centimeters,and its height is 20 centimeters.A cone is used to fill the cylinder wi

Lady_Fox [76]

Answer:

r u wanting the volume for each shape or what?

Step-by-step explanation:

4 0

3 years ago

Explanation on How to answer what is the density of an object that has a mass of 73,430 and the volume of 7 m3

scZoUnD [109]

Answer:

Density = 10,490 g/m³

Step-by-step explanation:

Density = mass ÷ volume

here mass = 73,430 g

volume = 7 m³

density = 73,430 ÷ 7

= 10490 g/m³

Density = 10,490 g/m³

7 0

2 years ago