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Musya8 [376]
3 years ago
13

A ball is thrown from first base to second base and then from second base to home plate. How many feet has the ball been thrown?

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

B. 90 + 90 √2

Step-by-step explanation:

From first base to the second base, it will travel 90 feet.

From the second base to the home plate, it will travel a longer distance.  How much?  Well, if you look at the layout of the field, you'll see that if you draw a line from second base to the home plate, you'll form two rectangular triangles, one with the 1st base, another one with the 3rd base.

The line from the 2nd base to home plate is the hypotenuse, which we can easily find by:

h²=90² + 90²

h = √(2 * 90²)

h = 90 √2

So, from second base to home plate, the ball has traveled 90 √2

Overall: 90 + 90 √2

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PLS HELP ME!!!!!!!!! I WILL MARK YOU!!!!!
Nikitich [7]

Answer:

7.92

Step-by-step explanation:

Given

c² + 0.1c - 24 ← substitute c = - 5.7 into the expression

= (- 5.7)² + 0.1(- 5.7) - 24

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4 0
3 years ago
Simplify your answer to the previous part and enter a differential equation in terms of the dependent variable xx satisfied by x
rusak2 [61]

Answer:

x'-5x=0, or x''-25x=0, or x'''-125x=0

Step-by-step explanation:

The function x(t)=e^{5t} is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.

Using rules of differentiation, we obtain that x'(t)=5e^{5t}=5x \text{ then }x'-5x=0. Differentiate again to obtain, x''(t)=25e^{5t}=25x=5x' \text{ then }x''-25x=0=x''-5x'. Repeating this process, x'''(t)=125e^{5t}=125x=25x' \text{ then }x'''-125x=0=x'''-25x'.

This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.

7 0
3 years ago
The mean amount of money spent on lunch per week for a sample of 458458 college students is $43$ 43. If the margin of error for
a_sh-v [17]

Answer:

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

Step-by-step explanation:

A confidence interval has two bounds, a lower bounds and an upper bound.

These bounds depend on the sample mean and the margin of error.

The lower bound is the sample mean subtracted by the margin of error.

The upper bound is the margin of error added to the sample mean.

In this problem, we have that:

The sample mean is $43.

The margin of error is $1.60 for a 99% confidence interval.

Lower bound: 43 - 1.60 = $41.40

Upper bound: 43 + 1.60 = $44.60

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

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