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3 years ago

What is the midpoint of the line segment with endpoints (-5.5, -6.1) and (-0.5,9.1)?

Mathematics

1 answer:

umka21 [38]3 years ago

4 0

(-3, 1.5)....simply add the x coordinates together, divide them by two, and then do the same for the y coordinates.

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Help im stuck haveing such a bad time understanding this

asambeis [7]

The answer would be 12 to the -10 because with multiplication you you add the -4 and -6

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3 years ago

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2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

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2 years ago

Suppose that all of the points on the circular dartboard shown are equally likely to be hit by a dart. If the radius of the shad

jekas [21]

This must double your chances so if i round the nearest whole number would be 8 any questions?

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2 years ago

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What is the constant of variation, k, of the line y = kx through (3,18) and (5,30)?

Fudgin [204]

Y is 18 so 18=3k
k=18/3
k=6 for (3,18)
for (5,30)let's see
y=30
30=5k
k=30/5
k=6

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3 years ago

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Are the numbers in front of either the x or y variables

Contact [7]

The answer is in the picture .:...

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2 years ago