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Slav-nsk [51]
3 years ago
7

What is the area, in cm2, of the circle shown above? Round your answer to the

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0
This might be wrong and I might be dumb but I got 153.86 because 7•7=49 & 49•3.14= 153.86
Drupady [299]3 years ago
4 0

Answer:

A = 97.968 cm^2 = 98.0 cm^2

Step-by-step explanation:

A = (78/360)*3.14*12^2

A = (78/360) * 3.14 * 144

A = (78/360) * 452.16

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What inequality does this number line show?
Len [333]

Answer:

x>2

Step-by-step explanation:

The arrow is facing the right hand side and the point on 2 isn't shaded so it's x greater than 2

8 0
2 years ago
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klasskru [66]

Answer:

E

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4 0
3 years ago
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Please help me!<br> x-1/12 = 7/2<br> a: 2<br> b: 6<br> c: 41<br> d: 43
Shalnov [3]
X=43/12 If you need work shown please tell me in the comments. Also please mark me as brainliest.
3 0
3 years ago
Solve the equation<br> 7+3m=28<br> A)m=18<br> B)m=11 2/3<br> C)m=9<br> D)m=7
Shtirlitz [24]
Firstly, you would subtract 7 from both sides, leaving you with 3m=21. You would then divide by three in order to be left with total value of m. 3m divided by 3 is m. 21 divided by 3 is 7. Therefore m=7 :)
6 0
3 years ago
WILL MARK BRAINLIEST!! The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2). Find th
irinina [24]
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
5 0
2 years ago
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