(70x10)+(6x1)+(4x1/10)+(2x1/100)+(9x1/1000)
Set 40 = 5x + 10
Subtract 10 on both sides, then divide 30 by 5
x = 6
We can start from the given line's coefficients and translate the line from the origin to the given point.
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
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For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
There is a way and you will find it but not from me
The slope of the line that contains the point (13,-2) and (3,-2) is 0
<em><u>Solution:</u></em>
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
<em><u>The slope of line is given as:</u></em>

Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)

<em><u>Substituting the values in formula, we get,</u></em>

Thus the slope of line is 0