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V125BC [204]
2 years ago
14

A restaurant wants to test a new in-store marketing scheme in a small number of stores before rolling it out nationwide. The new

ad promotes a premium drink that they want to increase the sales of. 20 locations are chosen at random and the number of drinks sold are recorded for 2 months before the new ad campaign and 2 months after. The 90% confidence interval to estimate the true average difference in nationwide sales quantity before the ad campaign and after is (3.96, 28.79). Which of the following is the appropriate conclusion?
1) We are certain the average difference in sales quantity between after the ad campaign to before for all stores is between -3.83 and 1.83.
2) We are 95% confident that the difference between the average sales after the ad campaign and the average sales before the ad campaign is between-3.83 and 1.83.
3) The proportion of all stores that had a difference in sales between after the ad campaign to before is 95%.
4) We are 95% confident that the average difference in the sales quantity after to before of the stores sampled is between -3.83 and 1.83.
Mathematics
1 answer:
spin [16.1K]2 years ago
4 0

Answer:

2 or 4

Step-by-step explanation:

You might be interested in
Find out the answers to this
meriva

Answer:

\tan \theta = - \frac{1}{5} = - 0.2

\cos \theta = 0.98

\sin \theta = - 0.196

Step-by-step explanation:

It is given that \cot \theta = - 5 and \theta is in the fourth quadrant.

So, only \cos \theta will have positive value and \sin \theta, \tan \theta will have negative value.

Now, \cot \theta = - 5

⇒ \tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5} (Answer)

We know, that \sec^{2} \theta - \tan^{2} \theta = 1

⇒ \sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019

{Since, \cos \theta is positive then \sec \theta will also be positive}

⇒ \cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98 (Answer)

We know, that \csc^{2} \theta - \cot^{2} \theta = 1

⇒ \csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099

{Since, \sin \theta is negative then \csc \theta will also be negative}

⇒ \sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196 (Answer)

4 0
3 years ago
What is 363 rounded to the nearest ten and hundred
anyanavicka [17]
3 is less than 5, so rounded to the nearest ten is 360.

6 is greater than 5, so rounded to the nearest hundred, our answer is 400.
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!!!!!!
GREYUIT [131]

Answer:

  The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.

Step-by-step explanation:

We're not sure what "system of equations" is being referenced here, since no equations are shown or described.

__

Perhaps your "system of equations" is ...

  f(x) = some equation

  g(x) = some other equation

Then the solution to this system of equation is the pair of values (x, y) that gives ...

  y = f(x) = g(x)

If x represents the month number, then the solution can be read from the table:

  (x, y) = (2, 4)

This is the month in which exports and imports were equal. Both numbers were 4 in February.

7 0
3 years ago
Can someone also help me with this one?
serg [7]

Answer:

120

Step-by-step explanation:

4 0
2 years ago
The zeros of the function are , 3, and , and the y-intercept of the function is located at .
MissTica

Answer:

The zeroes are -1, 3, and -2

The y intercept is located at (0,6)

Step-by-step explanation:

(x+2)=0

x=-2

The easiest way is to use an online graph like desmos and graph the problem there. You can see where the y intercept is.

8 0
2 years ago
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