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frozen [14]
3 years ago
7

Solve for y. -1 + y 8 < 15

Mathematics
2 answers:
dedylja [7]3 years ago
6 0
Y<2 is the answer that I got
stiks02 [169]3 years ago
3 0

Answer:

b.

Step-by-step explanation:

y is less than 2

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Determine whether the Mean Value Theorem applies to the function f(x)=2x^1/5 on the interval [-32, 32]
Anettt [7]

Answer

given,

f(x) = 2 x^{1/5}

interval = [-32, 32]        

differentiating the given equation

f'(x) = \dfrac{d}{dx}(2 x^{1/5})

f'(x) = \dfrac{2}{5x^{4/5}}

hence, the above solution is not defined at x = 0

and x = 0 lie in the given interval i.e. [-32, 32]

so, at x = 0 the function is not differentiable.

Hence, mean value theorem does not apply to the given function.

5 0
3 years ago
A plane intersects a triangular prism vertically as shown. Describe the cross-section shown here. A) pentagon B) rectangle C) tr
olga_2 [115]
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A cereal box has a length of 8 inches, a width of 2 inches and a height of 12 inches. What is the volume of the cereal box?
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Answer:

192 in cubed

Step-by-step explanation:

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6 0
3 years ago
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I NEED HELP PLEASE, THANK YOU!
bixtya [17]

Answer:

\sqrt{37}

Step-by-step explanation:

To find the distance between a point (m, n ) and the line

Ax + By + C = 0

d = \frac{|Am +Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n) = (6, 2) and rearranging the line

6x - y + 3 = 0 ← in general form

with A = 6, B = - 1 and C = 3 , then

d = \frac{|6(6)-1(2)+3|}{\sqrt{6^2+(-1)^2} }

   = \frac{|36-2+3|}{\sqrt{36+1} }

   = \frac{37}{\sqrt{37} }  

Rationalise the denominator by multiplying numerator/ denominator by \sqrt{37}

= \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

=\frac{37\sqrt{37} }{37} ← cancel 37 on numerator/ denominator

= \sqrt{37}

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3 years ago
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3 + 3 x 3 - 3 + 3 =?
SCORPION-xisa [38]
12, 3x3 = 9, +3 =12-3=9+3=12
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3 years ago
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