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galina1969 [7]
2 years ago
13

Angles of a triangle

Mathematics
1 answer:
xeze [42]2 years ago
8 0

Answer:

120 being vertically opposite angle of 120 and are equal

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How many jelly beans are in a 2-liter jar? HELP ME PLEASE
Galina-37 [17]

1. The number of sample size 1 jelly beans in a 2-liter jar is <u>645</u>.

2. The number of sample size 2 jelly beans in a 2-liter jar is <u>640</u>.

3. The number of sample size 3 jelly beans in a 2-liter jar is <u>637</u>.

<h3>What is a mathematical operation?</h3>

A mathematical operation is an expression involving the use of mathematical operands and operators to compute values.

Mathematical operations use variables, numbers, and operators (addition, subtraction, division, and multiplication).

<h3>Data and Calculations:</h3>

Total weight = 1,150g

Weight of the jar = 440g

The total weight of the jelly beans = 710g (1,150 - 440)

Sample Size 1: the number of jelly beans = 645 (710/22.0 x 20)

Sample Size 2: the number of jelly beans = 640 (710/22.2 x 20)

Sample Size 3: the number of jelly beans = 637 (710/22.3 x 20)

Thus, the number of jelly beans in a 2-liter jar depends on the sample size of the jelly beans.

Learn more about mathematical operations at brainly.com/question/20628271

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3 0
1 year ago
What is 78/10 expressed as a decimal?
SashulF [63]

Answer:

7.8

Step-by-step explanation:

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3 years ago
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What is the slope of the line on the graph?
netineya [11]

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Step-by-step explanation: This is none of your beeswax

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2 years ago
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The ubiquitous 12oz aluminum cans used to distribute drinks in this country have a diameter of approximately 2.75 inches and a h
gayaneshka [121]

Answer:

3.5%

Step-by-step explanation:

The volume of a cylinder = \pi r^2h

<em>r</em> = radius of cylinder,

<em>h</em> = height of cylinder

For the non-optimal can,

<em>r</em> = 2.75/2 = 1.375

<em>h</em> = 5.0

V = \pi(1.375^2)\times 5.0 = 9.453125\pi

<em />

For the optimal can,

<em>d</em>/<em>h</em> = 1,

<em>d</em> = <em>h</em>

2<em>r </em>=<em> h</em>

<em>r</em> = h/2

V = \pi\left(\dfrac{h}{2}\right)^2\times h = \pi\left(\dfrac{h^3}{4}\right)

They have the same volume.

<em />\pi\dfrac{h^3}{4} = 9.453125\pi<em />

h^3 = 37.8125

h=3.36 (This is the height of the optimal can)

r = \dfrac{3.36}{2} = 1.68 (This is the radius of the optimal can)

The area of a cylinder is

<em />A = 2\pi r(r+h)<em />

For the non-optimal can,

A = 2\pi\times\dfrac{2.75}{2}\left(\dfrac{2.75}{2}+5.0\right) = 17.53125\pi

For the optimal can,

A = 2\pi\times1.68\left(1.68+3.36\right) = 16.9344\pi

Amount of aluminum saved, as a percentage of the amount used to make the optimal cans = \dfrac{17.53125\pi - 16.9344\pi}{16.9344\pi}\times 100\% = 3.5\%

5 0
3 years ago
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