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AnnZ [28]
4 years ago
7

I need help with my math problem,..........................​

Mathematics
1 answer:
Evgesh-ka [11]4 years ago
8 0

is it linear?  Check the picture below, it looks like the graph of a LINE, so yes.

hmm so let's pick two points off the table, say (-9, -2) and (-1, -12) to get the equation

\bf (\stackrel{x_1}{-9}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-12-(-2)}{-1-(-9)}\implies \cfrac{-12+2}{-1+9} \\\\\\ \cfrac{-10}{8}\implies -\cfrac{5}{4}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=-\cfrac{5}{4}[x-(-9)] \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y+2=-\cfrac{5}{4}(x+9)~\hfill

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spin [16.1K]

Answer:  \bold{y=sin(4x)+3}

<u>Step-by-step explanation:</u>

\text{The standard form of a sine equation is: y=A cos(Bx - C) + D}\\\\\bullet\text{A = amplitude}\\\\\bullet\text{Period = }\dfrac{2\pi}{B}\\\\\bullet\text{Phase Shift = }\dfrac{C}{B}\\\\\bullet\text{D = vertical shift (up if positive, down if negative)}

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\implies \large\boxed{y=sin(4x)+3}

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