-7(sqrt(11)+sqrt(5))/6
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ANSWER
EXPLANATION
We want to find the exact value of cos(150°).
150° makes an angle of 30° with the positive direction of the x-axis and it is also in the second quadrant.
The cosine ratio is negative in the second quadrant.
Using the unit circle,
A closed shape with straight sides
Answer:
y = 7/2 -2
Step-by-step explanation:
if the slope of the first problem is -2/7 then its perpendicular is 7/2 (the exact opposite) and since the y- intercept is the b in Y= mx +b the intercept of the equation you’re trying to find is -2
1) y= - 2x² + 8x. It's a parabola open downward (a<0)
2) x - 2.23.y + 10.34 = 0 . Re-write it : y = (x/2.23) + (10.34/2.23), a linear equation.
To find the intersections between 1) & 2), let 1) = 2)
-2x² + 8x = (x/2.23) + (10.34/2.23)
-2x² + 8x - (x/2.23) - (10.34/2.23) =0 ; solve this quadratic for x values:
x' (that is A) = 0.772 & x" (that is B) = 3. (these are the values of x-intercept (parabola with line). To calculate the y-values, plug x' & x' in the equation:
for x' = 0.772, y = 0.34 → B(0.772 , 0.34)
for x" = 3, y = 0.016 → A(3 , 0.O16)
So B IS AT 0.34 Unit from the ground