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VARVARA [1.3K]
4 years ago
15

The hydrogen atom has one _____ and one _____.

Chemistry
2 answers:
larisa [96]4 years ago
8 0
<span>A single proton and a single electron.</span>
wolverine [178]4 years ago
5 0
The hydrogen atom has one Proton and one Electron. Hope I helped. =)
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A C=C bond is usually what kind of bond? Ionic Polar covalent Hydrogen Covalent
HACTEHA [7]

it is a polar covalent bond

7 0
4 years ago
The equilibrium constant is given for one of the reactions below.
Cerrena [4.2K]

Answer:

12.7551

Explanation:

The given chemical equation follows:

2HD(g)\rightarrow H_2(g)+D_2(g)

The equilibrium constant for the above equation is 0.28.

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

2H_2(g)+2D_2(g)\rightarrow 4HD(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{eq}'=(\frac{1}{0.28})^2

<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>

3 0
4 years ago
how many moles of ammonium chloride are required for a complete reaction with 420 mol of calcium hydroxide
Oxana [17]

3 KOH + H3PO3 = K3PO4 + 3 H2O  

moles KOH = 26.5 g/56.1 g/mol=0.472  

moles K3PO4 = 0.472/3 =0.157

3 0
3 years ago
Can somebody please help me please?
QveST [7]

Answer: if your having trouble with math there is a app called photo-math just snap a quick pic of your problem and they will give you an answer

Explanation:

4 0
3 years ago
Read 2 more answers
The Bohr theory can be extended to non-hydrogen one electron ions such as He+ and Li2+, in which case the energy depends on the
Wewaii [24]

Answer:

E =  1.5 x 10⁻¹⁷ J

Explanation:

The Rydberg equation for electronic transitions in the hydrogen atom  is

1//λ = Rh x ( 1/n₁² - 1/n₂²)

where            

           Rh : Rydberg´s constant 1.09737 x 10 ⁷ m⁻¹

           n₁ : Intial energy Level

           n₂ : Final energy Level

But for non-hydrogen one electron ions  such as He+ and Li2+ ²⁺ , the equation is similar but multiplied by Z²:

     1/ λ = Rh Z² x ( 1/n₁² - 1/n₂²)

I will work this problem by fist calculating 1/λ  and then use the equation E= hc/λ  where

h : Planck´s constant  6.626 x 10 ⁻³⁴ J s

c : Speed of light 3 x 10 ⁸

1/ λ =   1.09737 x 10 ⁷ m⁻¹ ( 3² ) x ( 1/1² - 1/2² )

1/ λ =   7.4 x 10⁷ m⁻¹

E = 6.626 x 10 ⁻³⁴ J s  x  3 x 10^8  m/s x   7.4 x 10⁷ m⁻¹

E =  1.5 x 10⁻¹⁷ J

6 0
3 years ago
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