it is a polar covalent bond
Answer:
12.7551
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 0.28.
We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>
3 KOH + H3PO3 = K3PO4 + 3 H2O
moles KOH = 26.5 g/56.1 g/mol=0.472
moles K3PO4 = 0.472/3 =0.157
Answer: if your having trouble with math there is a app called photo-math just snap a quick pic of your problem and they will give you an answer
Explanation:
Answer:
E = 1.5 x 10⁻¹⁷ J
Explanation:
The Rydberg equation for electronic transitions in the hydrogen atom is
1//λ = Rh x ( 1/n₁² - 1/n₂²)
where
Rh : Rydberg´s constant 1.09737 x 10 ⁷ m⁻¹
n₁ : Intial energy Level
n₂ : Final energy Level
But for non-hydrogen one electron ions such as He+ and Li2+ ²⁺ , the equation is similar but multiplied by Z²:
1/ λ = Rh Z² x ( 1/n₁² - 1/n₂²)
I will work this problem by fist calculating 1/λ and then use the equation E= hc/λ where
h : Planck´s constant 6.626 x 10 ⁻³⁴ J s
c : Speed of light 3 x 10 ⁸
1/ λ = 1.09737 x 10 ⁷ m⁻¹ ( 3² ) x ( 1/1² - 1/2² )
1/ λ = 7.4 x 10⁷ m⁻¹
E = 6.626 x 10 ⁻³⁴ J s x 3 x 10^8 m/s x 7.4 x 10⁷ m⁻¹
E = 1.5 x 10⁻¹⁷ J
